Question

basic calculus question

Answer 1

http://i.imgur.com/s8twTzj.png

Answer 2

I understand the derivative is the slope of the line, but I don't see how to find the slope if I am not given an equation

Answer 3

The segments are all linear.
So the slopes are constant (not changing) along a segment.

Remember how to find the slope of a line?

Answer 4

Honestly that was 4 years ago so no haha

Answer 5

Let's use numbers that are going to be easy to grab from the graph.
\[\Large\bf\sf f(0)\quad=\quad \frac{f(2.5)-f(-.5)}{2.5-(-.5)}\]

Answer 6

I'm just using the slope formula to find the slope of that line segment,\[\Large\bf\sf m\quad=\quad \frac{y_2-y_1}{x_2-x_1}\quad=\quad \frac{f(x_2)-f(x_1)}{x_2-x_1}\]

Answer 7

ah now I remember. thanks

Answer 8

Got it from there? :D k cool

Answer 9

f'(0) is what I meant to type above*
The slope of f at that point.
blah silly typo...