Question

Help!@roadjester

Answer 1

@roadjester

Answer 2

@UnkleRhaukus @radar @agent0smith

Answer 3

can you set up some simultaneous equations?

Answer 4

I tried but it does not make any sense...
Can you explain what is linearity(the calculation) I understand what it means, But I just don;t actually get it

Answer 5

apply Kirchoff's rules

Answer 6

KVL:
at loop1
Vs+R1i1+R2(i1-i2)=0
at loop 2
R2(i2-i1)-Is=0?

Answer 7

KCL:
at node 1:
i1+Is=i2?

Answer 8

the V_s should be of different sign to r1i1 etc

Answer 9

-Vs+R1i1+R2(i1-i2)=0

Answer 10

so R1 is the resistor at the top and R2 is the resistor in the middle?

Answer 11

yes..and node 1 is the node where R1 R2 and Is meets

Answer 12

i think that `i1+Is=i2` should be `i1=i2+Is`

Answer 13

why?

Answer 14

oh wait, maybe your right , `Is` is backwards

Answer 15

i1 and Is are entering the node and i2 is leaving

Answer 16

yeah i think you are right then

Answer 17

Do I have to do superposition first or linearity?
Please teach me step by step

Answer 18

but doesn't that make
`-Vs+R1i1+R2i2=0`

`-Vs+R1i1+R2(i1+Is)=0`

Answer 19

we are only allowed to use superposition and linearity in this question...

Answer 20

@UnkleRhaukus in -Vs+R1i1+R2(i1+Is)=0 are i1 and i2 suppose to be subtraction because they are moving in opposite directions?

Answer 21

thevenin is superposition

Answer 22

arn't they moving in the same direction?

Answer 23

@RaphaelFilgueiras I thought Thevenin was source transformation?

Answer 24

@UnkleRhaukus I am confused...
The symbols(i.e. i1 i2...etc) are confusing me...
They are in series, does that mean they have the same current?

Answer 25

@AntiNode , but i think the principle to do this transformation is superposition

Answer 26

@RaphaelFilgueiras I am new to circuit analysis maybe I am wrong but from what I know...
Superposition is when you only use one source at a time...
Voltage source will be a short circuit
Current source will be open circuit
dependent sources are not to be touched

Thevenin when you transform a current source that is parallel to a resistor into a voltage in series witht eh resistor...

Answer 27

http://en.wikipedia.org/wiki/Superposition_theorem

Answer 28

You are right...
But we are not allowed to use thevenin in this question unless they told us...