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Mathematics 13 Online
OpenStudy (anonymous):

Explain, without using a truth table, why(p∨¬q)∧ (q∨¬r)∧(r∨¬p)is true when p, q, and r have the same truth value and it is false otherwise

OpenStudy (kc_kennylau):

Just confirming, does v mean "or" while ^ means "and"?

OpenStudy (anonymous):

Yes

OpenStudy (kc_kennylau):

So when p=q, p\(\ne\)¬q and one of p and ¬q must be 1, so pv¬q=1.

OpenStudy (kc_kennylau):

Okay sorry I have no idea

OpenStudy (anonymous):

Ok

OpenStudy (kc_kennylau):

@hartnn

OpenStudy (kc_kennylau):

@Callisto

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