Consider a square with side 54.1 cm. Calculate the electric field at the center if one corner is occupied by a +41.9 µC charge and the other three are occupied by -27.3 µC charges.

Question

theeric · Answer

Hi! Do you have any idea where to start? Have you attempted a solution?

anonymous · Answer

yea i did but i cant seem to get the right answer

theeric · Answer

Let me see what I get, then...

theeric · Answer

Ar you using Coulomb's constant as $8.987\times 10^9\left[\dfrac{\rm{N\bullet m^2}}{\rm{C^2}}\right]$?

anonymous · Answer

yea E=k*q/r^2

anonymous · Answer

where r = sqrt2*54.1

theeric · Answer

And you used $r=\sqrt{54.1^2+54.1^2\ }$?

theeric · Answer

$\implies r^2=2(54.1)^2=5854\ \rm m^2$

theeric · Answer

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