Question

Help?
Solve the triangle.

B = 73°, b = 15, c = 8

Answer 1

(Assuming it's not a right triangle)
We can use the law of sines to solve for C.
\[\frac{\sin B}{b} = \frac{\sin C}{c}\]
Plug in your values and solve for C. (Remember to use your calculator in degrees mode.)

Answer 2

What the heck? Why does my school say to do b/sinB=c/sinC? Or does it do the same thing in the end?

Answer 3

They do the same thing in the end. It doesn't matter, as long as it's consistent. Keep the sines on the same side of the fraction.