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if sin (theta) = x/3 then sin (2 theta) = 2x/3 is this true?
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nope
not always
\[\sin \theta = \frac{ x }{ 3 }\] \[\sin 2\theta = \frac{ 2x }{ 3 }\] if no, then what is \[\sin 2\theta \]
\[\sin 2\theta=2 \sin \theta \cos \theta\]
\[\sin ^2 \theta +\cos ^2 \theta=1 \\cos^2 \theta=1-\sin ^2 \theta\\cos \theta =\pm \sqrt{1-\sin^2 \theta}\]
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the original question was \[\int\limits_{}^{} \frac{ 8 dx }{ (4x ^{2} +1)^{2} } \]
use substitution x=1/2 tan u dx=1/2 (1+tan ^2 u+1) du
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