Question

Can someone help me with these two problems.
Find f'(x)
f(x)=5x^3(2x^5-3x^3-4)
F(x)= cscx/x^3+5

Answer 1

Do you know the basic derivation formula?

Answer 2

yes....I worked out some of it but i'm stuck

Answer 3

What did you do so far?

Answer 4

\[5x ^{-3}(10x-9x^2)+(-15x ^{-4})(2x^5-3x^3-4)\]

Answer 5

then i got \[50x ^{-4}-45x-30x-45x+60x ^{-4}\]

Answer 6

Wait. Isn't \[f(x)=5x^3(2x^5-3x^2-4)\]

Answer 7

sorry i forgot the -
its \[5x^{-3}(2x^5-3x^3-4)\]

Answer 8

okay

Answer 9

Now, when you multiplied out 5x^-3(10x-9x^2), it's supposed to be (50x^-2)-(45x^-1)

Answer 10

ok so i subtract the exponents

Answer 11

\[x^a*x^b=x ^{a+b}\]
So
\[x^a*x^{-b}=x^{a-b}\]

Answer 12

so it will be \[5x ^{-2}-45x ^{-1}-30x ^{-9}-45x ^{-7}+60x ^{-4}\]

Answer 13

I actually got \[20x+60x^{-4}\]

Answer 14

ok