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Mathematics 8 Online
OpenStudy (anonymous):

How do I find the maximum power? (Picture attached)

OpenStudy (anonymous):

OpenStudy (anonymous):

The answer for (i) is 1-2cos(200t - 1.0472), if that's needed.

OpenStudy (anonymous):

first try to get the first Derivative then the first Derivative must be equal zero to getting the value of t which delivered the maximum power

OpenStudy (anonymous):

From which equation do I differentiate? The equation in the question, or the one from (i)?

OpenStudy (anonymous):

in the question p=f(t)

ganeshie8 (ganeshie8):

are u done wid part i) already ?

OpenStudy (anonymous):

Yes, 1-2cos(200t - 1.0472).

OpenStudy (ikram002p):

3esam so2al sehel :P =)

OpenStudy (anonymous):

I differentiated the thing, and got sin(200t) - (sqrt3)cos(200t) = 0... How do I continue?

OpenStudy (anonymous):

from this equation try to getting the value of t

OpenStudy (anonymous):

I'm not sure how to.

ganeshie8 (ganeshie8):

P = 1-2cos(200t - 1.0472) maximum value occurs when cos(200t-1.0472) = -1 so, max P = 1 -2(-1) = 1+2 = 3

ganeshie8 (ganeshie8):

for part iii, solve below : cos(200t-1.0472) = -1

OpenStudy (anonymous):

How did you come to that conclusion that [cos(200t - 1.0472) = -1] means it is the maximum value?

ganeshie8 (ganeshie8):

whats the range of cos(x) ?

ganeshie8 (ganeshie8):

[-1, 1] right ?

OpenStudy (anonymous):

Oh... I get it. Alright, thank you!

ganeshie8 (ganeshie8):

for other problems, u may do the calculus way as @esamalaa is doing... but its not required for this particular problem.. .

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