How do I find the maximum power? (Picture attached)
The answer for (i) is 1-2cos(200t - 1.0472), if that's needed.
first try to get the first Derivative then the first Derivative must be equal zero to getting the value of t which delivered the maximum power
From which equation do I differentiate? The equation in the question, or the one from (i)?
in the question p=f(t)
are u done wid part i) already ?
Yes, 1-2cos(200t - 1.0472).
3esam so2al sehel :P =)
I differentiated the thing, and got sin(200t) - (sqrt3)cos(200t) = 0... How do I continue?
from this equation try to getting the value of t
I'm not sure how to.
P = 1-2cos(200t - 1.0472) maximum value occurs when cos(200t-1.0472) = -1 so, max P = 1 -2(-1) = 1+2 = 3
for part iii, solve below : cos(200t-1.0472) = -1
How did you come to that conclusion that [cos(200t - 1.0472) = -1] means it is the maximum value?
whats the range of cos(x) ?
[-1, 1] right ?
Oh... I get it. Alright, thank you!
for other problems, u may do the calculus way as @esamalaa is doing... but its not required for this particular problem.. .
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