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sin(20-π) = sinΘ SOLVE ON THE INTERVAL: 0≤Θ<2π
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@mathstudent55 help pls?
use the law \[\sin \left( x-y \right)=\sin x \cos y-\cos x \sin y\]
ok then..?
then u have the value of \[\sin \left( 20-\Pi \right)\]
achieve it first
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but whgats sin20
are u have a calculator?
yea but i mean find exact value? shouldnt in be in like radical form?
for example: sqrt 3 /2 ?
wait never mind.. i get that part
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ok
wait but how do you get sin 20? cuz you cant use the sin(A-B) rule cuz theres nothing that willsubtract to get 20....
@amistre64
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