Question

how would I solve the equation, 3y^2-4y-15=0

Answer 1

quadratically .... either complete the square or use the formula

Answer 2

ax^2 + bx+c = 0

\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]

Answer 3

thank you

Answer 4

youre welcome

Answer 5

You can also try factoring.

Answer 6

\(3y^2 - 4y - 15 = 0\)

\(3y^2 - 9y + 5y - 15 = 0\)

\(3y(y - 3) + 5(y - 3) = 0\)

\( (y - 3)(3y + 5) = 0\)

Now set each factor equal to zero and solve for y.