Question

Solve for x
1-tan^2x = sin^2x + 1/sec^2x

Answer 1

x=0 or 180 or 360

Answer 2

right?

Answer 3

tan(x)=sin(x)/cos(x) , sec(x)=1/cos(x)

Answer 4

\[1-\tan^2x = \sin^2x + \frac{ 1 }{ \sec^2x } \]
\[1-\frac{ sin^2x }{ \cos^2x } = \sin^2x + cos^2x \]
\[1-\frac{ sin^2x }{ \cos^2x } =1 \]
\[\frac{ sin^2x }{ \cos^2x } =0 \]
\[\sin^2x= 0 \]

Answer 5

\[x=n \pi \]
n=0,1,2,.....