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Mathematics 6 Online
OpenStudy (anonymous):

how to do tan inverse (x) when x = 1 and 0

OpenStudy (anonymous):

\[\tan^{-1} (1)\] \[\tan^{-1} (0)\]

OpenStudy (anonymous):

one is equal to 0 and the other is equal to pi/2

OpenStudy (nincompoop):

use your calculator

OpenStudy (nincompoop):

but generally it means sin/cos = y/x = tan this means that the length of the adjacent side is the same as the length of the opposite side if you were to do a triangle it would be |dw:1393215893837:dw|

OpenStudy (nincompoop):

|dw:1393215934391:dw|

OpenStudy (nincompoop):

r = sqrt(2)

OpenStudy (anonymous):

I'm not into the answer, i just wanna know how it's done

OpenStudy (nincompoop):

you need to know the concept to know how it is done tan^-1 or the arctan converts it to degrees

OpenStudy (anonymous):

yes, i know that...

OpenStudy (anonymous):

|dw:1393216173880:dw|

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