Question

solve the system using the substitution method .1x+.7y=-1.3 and .8x-.5y=7.9

Answer 1

any ideas?

Answer 2

need help

Answer 3

I know, but I like to see if you have any thoughts first, so why don't we start by solving one of our eq for y

Answer 4

can you do that?

Answer 5

would start by doing this y=-(13/7)-x

Answer 6

can you show mw all of your steps please?

Answer 7

10(.1X+.7Y)=(-1.3)10
THEN would solve for y

Answer 8

by subtracting x and divideing the 7

Answer 9

when you divide by 7, do you divide the whole side or only part of it?

Answer 10

the whole side so i would have y=-(13/7)-(1/7)x

Answer 11

yup

Answer 12

try pluging it in i keep getting crazy answers

Answer 13

so now, you are going to put that y=blahblah into your other eq and solve for x

Answer 14

show me your steps again?

Answer 15

8x-5(-(13/7)-(1/7))=79

Answer 16

you forgot something

Answer 17

ya the x

Answer 18

yup so now, step by painfully slow step please :)

Answer 19

8x+(65/7)+(5/7)x

Answer 20

(61/7)x +(65/7)=79

Answer 21

ok make sure you keep an = sign somewhere on your paper

Answer 22

wait

Answer 23

ok go (i'm really bad at 7*8 oops)

Answer 24

(61/7)x=(488/70)

Answer 25

x=8

Answer 26

might I make a suggestion, get rid of the fractions first

Answer 27

it'll make life easier

Answer 28

yes so in the end i go x=8 and y=-3 is this correct

Answer 29

looks like it let me check

Answer 30

thanks for the help

Answer 31

yup

Answer 32

thats correct well done, just be careful with your distributions

Answer 33

can you help me with this one as well m^2=19

Answer 34

how do you undo a square?

Answer 35

square root but this cannot be simplified into a whole number so the solution would be - square root of 19 and quire root of 19 correct

Answer 36

mmhmm customarily we say \(\frac{+}{} \sqrt{19}\)

Answer 37

yes

Answer 38

that's all there is to it

Answer 39

thank you

Answer 40

np :)