Ask your own question, for FREE!
Physics 42 Online
OpenStudy (anonymous):

I need some serious help please

OpenStudy (anonymous):

OpenStudy (anonymous):

Let's look at how acceleration is defined. Simply, it is\[a = {\Delta V \over \Delta t}\] or the change in velocity over the change in time. If we must determine acceleration from only distance and time, we can use the following expression, \[a ={2\Delta r \over \Delta t^2}\] Now that we have the math, let's think about it conceptually. If an object takes 10 seconds to fall 10 meters when measured accurately, it has an acceleration of 0.2 m/s^2. If we goofed up our experiment and measured a time greater than 10 seconds, but measured the distance correctly as 10 meters, what impact would that have on our calculated value of acceleration? If we goofed up our experiment and measured a distance greater than 10 meters, but measured the time correctly as 10 seconds, what impact would that have on our calculated value of acceleration? For what it is worth, air resistance will slow you down causing a lower than accurate calculated acceleration value. The size of the object shouldn't matter in the absence of air resistance.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!