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Pre calculus: Inverse functions (Question in reply)
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\[\sec ^-1 (1)\]
An angle whose secant is 1. An angle whose cosine is 1/1 = 1. Name it!
180 degrees?
\(\bf sec^{-1}(1)\implies sec(\theta)=1\implies \cfrac{1}{cos(\theta)}=1\implies \cfrac{1}{1}=cos(\theta) \\ \quad \\ \implies cos^{-1}\left(\cfrac{1}{1}\right)=cos^{-1}[cos(\theta)]\implies cos^{-1}(1)=\theta\)
check your Unit Circle for it
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For what exactly?
for the angle WHOSE COSINE is 1
pie. correct? or, 180 degrees to be specific.
is that what you've got from the Unit Circle?
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yeah, thinking about a unit circle, it should actually be 0 degrees, correct? Else 180 would have been -1.
yeap, 180 would be -1 0 or \(2\pi\) are 1
Then I thank thee kind sir. You have been most helpful.
yw
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