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sin(3theta) = -1 find the solution set. I only got the first radian right. which was (pie/2)
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sin = -1 when angle is 3pi/2 plus multiples of 2pi 3pi/2 + 2pi = 7pi/2 --->theta = 7pi/6
\[\text{lets see begin with breaking this up.}\\sin(3\theta)=sin(\theta +2\theta) \\sin(A+B)=sinAcosA+sinAcosB \\ proceed--->try \]
and dumbcow how did you get that method of doing multiples of 2
i dont think mebs method applies to your problem
yes keep adding 2pi to get more solutions
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yea i noticed . it doesnt
but where did you get 2pie from. ?
thats the num of radians in a circle
hmmm... it is to tedious don't bother I was thinking of something else.
its alright mebs. And dumbcow thanks I figured it out.
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