One leg of a right triangle is 10m less than the hypotenuse, and the other leg is 5m less than the hypotenuse. find the length of all three sides
Okay. It always helps to set up an equation. You should know that a^2 + b^2 =c^2, yes?
yeah i dd that
If c is the hypotenuse, and a and b are the two side. Then the a is going to be c-10 (a = c-10m) and b is going to be c-5.
Understand that?
yeah
Alright. From there its just a whole bunch of multiplication after you plug it back in to the equation. a= c-10 b = c-5 a^2 + b^2 = c^2 (c-10)^2 + (c-5)^2 = c^2
You'll want to do two FOILS, and then do some adding/ subtracting from both sides to get c. From there you'll know a = c-10 and b = c-5, so those will both be really simple to do.
Hopefully that all makes sense. All you've got left to do now is a little tedious multiplication and algebra. Any questions?
No, it makes sense thanks.
Alright. Good luck with the problem. That equation looks pretty ugly/ easy to make a careless mistake on.
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