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(1+i) is a root of the equation x^3+2x^2-6x+8=0. find the other roots of the equation
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i think 1-i is also root
the complex conjugate root theorem states that if P is a polynomial in one variable with real coefficients, and a + bi is a root of P with a and b real numbers, then its complex conjugate a − bi is also a root of P
I used synthetic division to figure out that 4 is also a root. Which leaves you with a simplified equation of x^2-2x+2. But idk how to simplify that equation
Would you plug it into the quadratic to get 1-i?
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