Question

What is the set of zeros in the function?
f(x)= (x^2 + 2500) x^2 - 1600)

Answer 1

f(x)= (x^2 + 2500) (x^2 - 1600) ?

Answer 2

yes

Answer 3

if so, the roots for f(x) is when x^2 - 1600 = 0
by using difference square formula, it can be factored be
x^2 - 1600 = 0
x^2 - (40)^2 = 0
(x + 40)(x - 40) = 0
then setting each factor to zero, and solve for x

Answer 4

Thanks!

Answer 5

wait, is the roots just for real solution, or can the imaginary root be allowed ?