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Trigonometry 17 Online
OpenStudy (theraggedydoctor):

Clara and The Doctor are running from some Daleks. They spot the building their TARDIS materialized on, and figure they will be safe if they can get to the TARDIS in time. The building is 17 feet tall, and has a board leading up to the top that is x feet long. The board is at a 29° angle with the ground. How far will they have to run to get to the top of the building if they run up the board? (Now, Daleks can’t make it onto this board without any legs so you have some time to answer this question) Lol i made up my own trig question as an assignment and now i need help solving it.... kinda s

OpenStudy (theraggedydoctor):

i have a picture hang on a sec lol

OpenStudy (anonymous):

this is soooo cool. but i think david is the best doctor

OpenStudy (theraggedydoctor):

Yeah i know.. i just used the latest one XDD but ten will always be my favorite

OpenStudy (anonymous):

nice job on the prop

OpenStudy (anonymous):

yea me too

OpenStudy (theraggedydoctor):

OpenStudy (theraggedydoctor):

XD how come it always says im typing

OpenStudy (anonymous):

idk

OpenStudy (anonymous):

well see ya

OpenStudy (anonymous):

:)

OpenStudy (theraggedydoctor):

k seeya XD :(

OpenStudy (theraggedydoctor):

@e.mccormick can you help? XD

OpenStudy (e.mccormick):

Well, do you know your trig ratios? SOC CAH TOA?

OpenStudy (theraggedydoctor):

yeah :D sin = Opposite/hypotenuse cos = adjacent/hypotenuse tan = opposite/adjacent right?

OpenStudy (theraggedydoctor):

im not actually typing lol theres something wrong :S

OpenStudy (e.mccormick):

Yep. For the non-90 angles in a right triangle, there is the side opposite, the side adjacent, and the hypotenuse; or O, A, and H for short. SOH means \(\sin\theta = \dfrac{O}{H}\) CAH means \(\cos\theta = \dfrac{A}{H}\) TOA means \(\tan\theta = \dfrac{O}{A}\)

OpenStudy (e.mccormick):

There can be delay in the typing update. OK, so for your question, you have an \(\angle \theta\), one known side, and one unknown side. Which of those has your three things?

OpenStudy (theraggedydoctor):

SOH? Would it be: sin65 = 17/x ???

OpenStudy (e.mccormick):

65? \(\sin 29^{\circ} = \dfrac{17}{x}\)

OpenStudy (theraggedydoctor):

Oh sorry i'm looking at a different question *facepalm* yeah i meant sin29 lol

OpenStudy (e.mccormick):

OK. Then solve for x.

OpenStudy (theraggedydoctor):

Multiply both sides by x right?

OpenStudy (e.mccormick):

Yes.

OpenStudy (theraggedydoctor):

(x)sin29 = 17

OpenStudy (e.mccormick):

And then?

OpenStudy (theraggedydoctor):

Divide both sides by 17?

OpenStudy (theraggedydoctor):

wait NO lol divide both sides by sin29

OpenStudy (e.mccormick):

\(\sin 29^{\circ} = \dfrac{17}{x}\) \(\sin 29^{\circ}\cdot x = \dfrac{17}{x}\cdot x\) \(\dfrac{\sin 29^{\circ} x}{\sin 29^{\circ} } = \dfrac{17}{\sin 29^{\circ} }\) \(x = \dfrac{17}{\sin 29^{\circ} }\) It will take a calculator or trig table at that point.

OpenStudy (theraggedydoctor):

x = approx. 35.07? idk the windows calculator is weird lol is that right?

OpenStudy (e.mccormick):

35.0653107737 bla bla bla So ya. 35.07 units. And since you listed units in the question, it is generally good to have them in the answer.

OpenStudy (theraggedydoctor):

Thanks so much that really helped :)

OpenStudy (e.mccormick):

np. Have fun!

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