find the error in this problem:
please help
Problem #1, probably the one you're looking for, is that when we divide by x and (x-4) we are assuming that neither is 0. And that makes sense, since division by zero is kind of a problem. But if we have that either x is 0 or x is 4, then we have a HUGE problem with our ratio because we have 0 in the denominator.
Oaktree your wrong
what is it? im so confused @naahhbass
stretch out the problem as seen in the link you posted then substitute the unnecessary solutions for those exercisers, k and you cant divide the sums becuz theirs no X^3 to be divided ( x-4)^3
does that explain it well
if it does medal please
yes thank you!
just note that these problems may try to trick you but remember theirs a solution to everything mami :)
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