The quantity of charge Q in coulombs (C) that has passed through a point in a wire up to time t (measured in seconds) is given by
Q(t) = t3− 2t2 + 3t + 1.
[See this example. The unit of current is an ampere 1 A = 1 C/s.]

Question

The quantity of charge Q in coulombs (C) that has passed through a point in a wire up to time t (measured in seconds) is given by 
Q(t) = t3− 2t2 + 3t + 1.
 [See this example. The unit of current is an ampere 1 A = 1 C/s.]

anonymous · Answer

@mathmale

anonymous · Answer

what are we supposed to find

mathmale · Answer

Hello, M,
Weren't there instructions regarding what you are to do or to find in this question?

anonymous · Answer

(a) Find the current when t = 0.1 s.
(b) Find the current when t = 1 s.

At what time is the current the lowest?

anonymous · Answer

to find  the current differentiate wrt   to t
then put t=.1and t=1s

mathmale · Answer

nkaadi and I will need to assume that you know differential calculus already; do you?

anonymous · Answer

to find the minimum current 
equate the new equation to 0 
yes i know sir

anonymous · Answer

and find t

anonymous · Answer

hope you understood

anonymous · Answer

|dw:1393377749029:dw|