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Need help solving for r! 6^(-r-1)=216
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would this be 6^(-r-1)=6^3?
and then -r-1=3?
Note that you have 6 as base on both sides of your initial equation. If the bases are the same, as they are here, then you may equate the exponents, obtaining the much simpler equation -r-1=3, exactly as @ali1029 has already stated. Solve this for r. In your shoes, I'd add r to both sides, and then subtract 3 from both sides. Go for it.
i got r= -4 thank you very much for explaining!! :)
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