Question

Need help solving ln(x+6)-lnx=ln79

Answer 1

would that be ln(x+6)/lnx=ln79?

Answer 2

\[\ln a - \ln b = \ln \frac{a}{b}\]

Answer 3

what would i do after that?

Answer 4

once you have

ln[something] = ln[something else]

raise both sides to the base of the log

e^ln[something] = e^ln[something else]

then the logs and the base will cancle

something = something else

Answer 5

I'm sorry but that really confused me :o

Answer 6

so i would do lne^(x+6)/(x)=lne79??