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Algebra
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z varies directly with x and inversely with y. When x=6 and y=2, z=15. Find z when x=4 and y=9
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Can someone explain how to do this?
start out with z=
Then put the directly stuff on top and the inversely stuff on the bottom.
I made a proportion of 6/15 4/z
I tried to cross multiply and divide and got 10
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Then multiply by k for the constant.
How do you determine the constant?
\[z=\frac{kx}{y}\] \[\frac{zy}{x}=k\] \[\frac{15(2)}{6}=\frac{9z}{4}\]
Here is how to find k Replace z with 15, y with 2 and x with 6 and solve for k
2.2 repeating?
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Is that what k equals?
\[15=\frac{6k}{2}\] \[30=6k\] \[5=k\]
Isn't it 15 times 2?
Yes. and 15 times 2 = 30
and isn't it 9k/4
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