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Chemistry 12 Online
OpenStudy (anonymous):

I tried to solve this question but I feel like my answer came out to be too large... Determine the formula mass of Pb(NO3)2 in g/mol and convert 0.250g Pb(N)3)2 to moles Pb(NO3)2. I did the first part of the question and got an answer of 331g/mol. Then for the second part I ended up with 1324 moles. I'm new to chemistry but to me that seems like a high number of moles? I set it up as: 0.250g/1mol=331g/mol/Xmol 0.250gX=331g/mol 0.250gX/0.250gX 331g/mol/0.250gX X=1324 moles

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