Question

My last question yay!!!
(3-2i)(3-2i)
I got 13???
Maybe im wrong

Answer 1

Yea, you're suppose to have an i term somewhere still.

Answer 2

well you can always check by expanding:
(3-2i)(3-2i)=9-6i-6i+4i^2 = 9+4-12i = 13-12i. dont forget your i terms!

Answer 3

yeah me too getting the same as @LifeEngineer

Answer 4

@sahmad u forget to add i to ur terms

Answer 5

I got it thanks so much!!! I see what I did :) off to bed finally

Answer 6

@LifeEngineer

Ur answer is wrong

(3-2i)(3-2i)
Multiply
3*3-3*2i-2i*3+2i*2i
9-6i-6i+4i^2
9-12i+4i^2 i^2=-1
9-12i+4(-1)
9-12i-4
5-12i

Answer 7

@Nurali

Right you are! Forgot to carry my negative on the i^2... Its been a while since I've done these types of problems