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Mathematics 11 Online
OpenStudy (anonymous):

I will give medals!!

OpenStudy (anonymous):

7/3*1/2=? then 7/3*21/4=? then ?+?=? please fill in the question marks

OpenStudy (anonymous):

@SnowCrystal, @madeline.grey, @linda3, @kturpy, @DollyAcquah, @helpmeplease1239, @wolfe8, @orion92898 someone please help

OpenStudy (snowcrystal):

hello do u know what the 1st step is Doll

OpenStudy (snowcrystal):

7*1= 7 3*2= 6 your 1st answer is 7/6 or 1 and 1/6

OpenStudy (anonymous):

what does * it means,does it mean times

OpenStudy (anonymous):

\[\frac{ 7 }{ 3 }\times \frac{ 1 }{ 2 }\]

OpenStudy (anonymous):

yea

OpenStudy (snowcrystal):

u multiply across the top then do the same for the bottem

OpenStudy (anonymous):

kk

OpenStudy (anonymous):

7/6+7/3x21/4=?

OpenStudy (anonymous):

?=1.15 ?=12.075 =13.225

OpenStudy (anonymous):

does this help

OpenStudy (snowcrystal):

7*21= 147 3*4= 12 to get 147/12 or 12 and 1/4

OpenStudy (snowcrystal):

then u want to add both answers together right?

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

jen you there

OpenStudy (anonymous):

does this help

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

does what helP? it needs to stay in fraction form

OpenStudy (snowcrystal):

7/6 + 147/12 both denominators have to be the same for addition and subtraction so we make it 12 7*2= 14 6*2= 12

OpenStudy (snowcrystal):

so now we have 14/12 +147/12

OpenStudy (anonymous):

yup

OpenStudy (snowcrystal):

now that the denominators are the same we add only the top numbers

OpenStudy (anonymous):

161/12

OpenStudy (anonymous):

i put it in wrong but i do not know how to put it in let me look

OpenStudy (anonymous):

can you take like a picture of the problem?

OpenStudy (snowcrystal):

now our last step is to make is a mixed number with is 13 and 5/12

OpenStudy (snowcrystal):

how i did it all in my head

OpenStudy (anonymous):

awesome

OpenStudy (snowcrystal):

the best thing to do if u need to show ur work is to go back through every comment and write down what is there

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