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The equation of line AB is (y−3) = 5 (x − 4). What is the slope of a line perpendicular to line AB?
sorry can not help
I first would attempt to put that equation into the slope intercept form "y=mx+b"
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y=5x-20 + 3 y = 5x - 17 The coefficient of x is a 5 The slope of line AB is 5, but that is not what you are looking for. The line that is perpendicular to AB will have a slope that equal to the negative reciprocal of this 5 which is -1/5
Got you !!! Thaaaaaaaaaaaaanks @radar
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