Mathematics
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OpenStudy (anonymous):
Find the slope of a line parallel to each of the following lines.
A. y-x=-3
B. 5y+3x=1
C. 2x-5y+10=0
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OpenStudy (anonymous):
Y=MX+B FORM?
OpenStudy (anonymous):
Yup that is the first step
OpenStudy (anonymous):
First rearrange the equation into that form
OpenStudy (anonymous):
y=x+3
OpenStudy (anonymous):
Now, do I subtract 3?
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OpenStudy (anonymous):
Well we know that the slope of a parallel line will have the same slope as the original line
OpenStudy (anonymous):
so all ya gotta do is fine the slope of this line
OpenStudy (anonymous):
Now your equation is in the form
y=mx+b
where m=slope
OpenStudy (anonymous):
Yeah, I know
OpenStudy (anonymous):
So what is m in this equation?
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OpenStudy (anonymous):
Btw you are wrong the first equation becomes
y=x-3
OpenStudy (anonymous):
The m is stil the same in this case. SO in reality it wont change the answer
OpenStudy (anonymous):
So what is our m in y=x-3?
OpenStudy (anonymous):
x?
OpenStudy (anonymous):
Nopeeee
y=mx+b
y=1x-3
So in this case our m=1 and b=-3
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OpenStudy (anonymous):
oh, so I add 3?
OpenStudy (anonymous):
can you show how u got that?
OpenStudy (anonymous):
OKKKKKKKK
listen up kid
OpenStudy (anonymous):
We moved our equation into the form y=mx+b
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
so we started off with y-x=-3
and then we converted it into y=x-3
OpenStudy (anonymous):
y=1x-3
is in the form y=mx+b
OpenStudy (anonymous):
Where our m=1 and b=-3
OpenStudy (anonymous):
Okk lemme give you another example
Lets say we have the equation y=3x+5
The equation is in the form y=mx+b
where m=3 and b=5
OpenStudy (anonymous):
Do you follow?
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OpenStudy (anonymous):
Basically the m is the number in front of the x
OpenStudy (anonymous):
Yes, I get it and sorry, I was away for a couple minutes...
OpenStudy (anonymous):
so m is our slope so for our first equation the slope is 1
OpenStudy (anonymous):
ok, question 2 know
OpenStudy (anonymous):
ok first put it into y=mx+b form
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OpenStudy (anonymous):
5y=3x+1
OpenStudy (anonymous):
3-3 cross out; 5-3=2
OpenStudy (anonymous):
2y=1/2
OpenStudy (anonymous):
whatttt what is 3-3 crossout???
OpenStudy (anonymous):
subtract 3 from 5 and from 3
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OpenStudy (anonymous):
We are trying to isolate y
Sooo we have 5y=-3x+1
Now we divide the whole equation by 5 and what do we get?
OpenStudy (anonymous):
So, I was wrong?
OpenStudy (anonymous):
Yup
OpenStudy (anonymous):
oh
OpenStudy (anonymous):
I got 3/5
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OpenStudy (helpblahblahblah):
me what?
OpenStudy (anonymous):
y-x=-3
OpenStudy (helpblahblahblah):
i dunno sorry
OpenStudy (anonymous):
it's ok
OpenStudy (helpblahblahblah):
okay