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Trigonometry
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cos(5/13-3/5) find the exact value
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\[\cos \left( \frac{ 5 }{ 13}-\frac{ 3 }{ 5 } \right)\]
help
well you need 2 right triangles |dw:1393477116473:dw| next use the difference expansion for cos cos(X - Y) = cos(X)cos(Y) + sin(X)sin(Y) find sin(X) and sin(Y) from the triangles. hope it helps
so the answer is 33/65
nope not the correct answer... notice how the expansion has a + sign....
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a= 12 but + sign I don't get
ok... wel its the difference equation for cos cos(A -B) = cos(A)cos(B) + sin(A)sin(B)
cos(a)=5/13 cos(b)=-3/5+sin(a)=12/13 sin(b)=4/5 so than it is 18/65 if not how do you work it out
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