Question

Solve the system of equations.

5x + y = 9
3x + 2y = 4

(-2, 5)

(1, 4)

(2, -1)

(4, -4)

Answer 1

You could solve by substitution

Answer 2

easiest way would be to isolate y in the first equation then sub that back into the 2nd equation. Thus, solving by substitution

Answer 3

lets me help you get started...
5x + y = 9 -- subtract 5x from both sides
y = -5x + 9

now sub -5x + 9 in for y in the 2nd equation and solve for x.
Now, show me what you can do :)

Answer 4

@sourwing

Answer 5

If you like elimination:
\[\LARGE 5x + y = 9\]
\[\LARGE 3x + 2y = 4\]
*-2
\[\LARGE -10x-2y=-18\]
\[\LARGE 3x+2y=4\]

And staph it, stop being lazy and do some work c:

Answer 6

dont feel like doing it im sick in the hospital so no i dont feel the need to

Answer 7

That's the first wrong answer I've seen on openstudy.

Answer 8

lol^

Answer 9

then whats the correct answer

Answer 10

I am sick too....so I guess I don't need to give you the answer

Answer 11

Last time I was in the hospital I taught myself linear algebra.

Answer 12

Which, by the way, says:\[\left[\begin{matrix}5 & 1 & 9 \\ 3 & 2 & 4\end{matrix}\right]\]\[\left[\begin{matrix}1 & \frac{1}{5} & \frac{1}{9} \\ 3 & 2 & 4\end{matrix}\right]\]\[\left[\begin{matrix}1 & \frac{1}{5} &\frac{1}{9} \\ 0 & \frac{7}{5} & \frac{-7}{5}\end{matrix}\right]\]\[\left[\begin{matrix}1 & 0&2 \\ 0 & 1&-1\end{matrix}\right]\]x=2 y=-1

Answer 13

cool i dont care okay im in the HOSPITAL for a reason not at home!?!?!? DUHHHHH so i dont know why your complaining @texaschic101

Answer 14

I understand your in the hospital for a reason, and I am sorry about that. But that doesn't mean you are entitled to get all the answers and do none of the work. Thats all I am saying. And if you didn't feel you needed to do the work, then I didn't feel the need to give you the answer.

Answer 15

Soo, whats the answer? @texaschic101 XD