Which is the solution of -5+2x^2=-6x

Question

anonymous · Answer

First of all, try getting all terms on one side of the equation.

anonymous · Answer

$$2+ or -\sqrt{4-(-4)(6)(-5)} \over 5$$

anonymous · Answer

2x^2 - 5 = -6x
2x^2 + 6x -5 = 0
(2x

anonymous · Answer

that's as far as i got, i have to go though. See if you can figure it out. i don't think it's set up the way you put it

anonymous · Answer

the equation i put is one of the answers

anonymous · Answer

$$B. -5+or - \sqrt{25 - (4)(2)(6) }$$

johnweldon1993 · Answer

So get everything on one side and set it equal to 0 (we'll use the quadratic formula here

-5+2x^2=-6x
becomes

2x^2 + 6x - 5

So we have everything we need...
A = 2
B = 6
C = -5

In the quadratic formula

$$\large \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$

Just plug in all your numbers and you'll have your answer

anonymous · Answer

Thank you @johnweldon1993

johnweldon1993 · Answer

Anytime :)