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Which is the solution of -5+2x^2=-6x
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First of all, try getting all terms on one side of the equation.
\[2+ or -\sqrt{4-(-4)(6)(-5)} \over 5\]
2x^2 - 5 = -6x 2x^2 + 6x -5 = 0 (2x
that's as far as i got, i have to go though. See if you can figure it out. i don't think it's set up the way you put it
the equation i put is one of the answers
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\[B. -5+or - \sqrt{25 - (4)(2)(6) }\]
So get everything on one side and set it equal to 0 (we'll use the quadratic formula here -5+2x^2=-6x becomes 2x^2 + 6x - 5 So we have everything we need... A = 2 B = 6 C = -5 In the quadratic formula \[\large \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\] Just plug in all your numbers and you'll have your answer
Thank you @johnweldon1993
Anytime :)
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