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Geometry 14 Online
OpenStudy (avai70178):

The figure below shows a rectangle ABCD having diagonals AC and DB. A rectangle ABCD is shown with diagonals AC and BD. Anastasia wrote the following proof to show that the diagonals of rectangle ABCD are congruent. Anastasia's proof: Statement 1: In right triangle ADC, the sum of the squares of sides AD and DC is equal to the square of hypotenuse AC so that AD2 + DC2 = AC2 and in right triangle ABD, the sum of the square of sides AD and AB is equal to the square of hypotenuse DB so that AD2 + AB2 = DB2 (by symmetric property of equality Statement 2: AB = DC opposite sides of a rectangle

OpenStudy (avai70178):

Statement 3: AC2 = DB2 (from statements 1 and 2) Statement 4: AC = DB (taking square root on both sides of AC2 = DB2) Which statement in Anastasia's proof has an error? Statement 1 Statement 3 Statement 2 Statement 4

OpenStudy (anonymous):

The justification for step one seems incorrect, the more appropriate justification would be the Pythagorean theorem.

OpenStudy (avai70178):

well the problem is we haven't learned that yet. for some reason we are doing proofs before like actual real geometry. so which one would you chose

OpenStudy (anonymous):

I would choose statement 1.

OpenStudy (avai70178):

thank you

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