Find the 23rd term of -12, -15, -18.
do you know what the common ratios is?
The difference is about -3?
So it's an arithmetic series?
ok so the common ratio is -3 the 1st term as you can see, is -12 so now that we know those two fellows we'll use them in \(\Large \bf a_{\color{red}{ n}}=a_1+({\color{red}{ n}}-1){\color{blue}{ d}} \\ \quad \\ a_1=\textit{first term}\\ {\color{blue}{ d}}=\textit{common ratio} \\ \quad \\ \Large a_{\color{red}{ 23}}=-12+({\color{red}{ 23}}-1){\color{blue}{ -3}}\)
-12 + 22 - 3 = 7?
well... the 22 * -3
Oh I read that as subtract 3.
-78?
hmm my bad .... \(\large a_{\color{red}{ n}}=a_1+({\color{red}{ n}}-1){\color{blue}{ d}} \\ \quad \\ a_1=\textit{first term}\\ {\color{blue}{ d}}=\textit{common ratio} \\ \quad \\ \large a_{\color{red}{ 23}}=-12+({\color{red}{ 23}}-1)({\color{blue}{ -3}})\)
-78? \(\Large \checkmark\)
So for other problems, I just find the difference and plug in the values?
yeap
Thanks :)
yw
Join our real-time social learning platform and learn together with your friends!