Question

Can someone please help me with this?

Answer 1

Find \[P _{k+1}\] for the given \[P _{k}\]

Answer 2

\[P _{k}=k^2(2k+2)\]

Answer 3

I don understand this, and I would love it if someone could show me how to work the problem!

Answer 4

looks like you'd just set k = k+1 and expand

Answer 5

I don't even know how to do that.

Answer 6

\(\bf P_{\color{red}{ k}}={\color{red}{ k}}^2(2{\color{red}{ k}}+2)\qquad k=k+1\qquad P_{\color{red}{ k+1}}=({\color{red}{ k+1}})^2(2({\color{red}{ k+1}})+2)\)

Answer 7

Is that the answer?

Answer 8

where you see a \(k\) replace it by \(k+1\) and use parentheses

Answer 9

\[P _{k}=k^2(2k+2)\]
\[P _{k+1}=(k+1)^2(2(k+1)+2)\]

Answer 10

Then I solve that? I dont know how....