a car travels at 3m/s but is accelerating constantly at 2/3 m/s. A bike is traveling at 5m/s. Find the point at which the car has travelled twice as far from the start as the bike. Thanks :)
your welcome :D
would you be able to help out?
That depends if you are ready to help yourself ;-) alright.. i believe you need to calculate the time? right?
yeah
soo.. yo uunderstnd that problem?!
yeh?
so then.. can you start ..? i ll help you if you get stuck!
i dont know how to start though
well.. imagine that the biker boy travels X distance in time t then in the same time how much distance should the car travel?
2x
ok.. so .. now set up equations biker boy traveling at 5m/s, he travels x meters in t sconds. waht equation can u set up?!
5=x/t
good now lets go to the car car starts with 3m/s.. accelerates at 2/3 m/s^2 . travels a distance 2x in time t.. what equation can u set up?!
ummm.... 2/3=3/t ???
do you think thats right? :P
madam.. acceleration is NOTTTT equal to velocity over time.. this is like some sort of misconception students have :-/ acceleration is CHANGE IN VELOCITY over time.. it tells you how much a velocity is changing over time imagine if i said velocity = position /time.. does that make sense ?? no right?? velocity = CHANGE in position / time!! get it?!?
ohhh okay
so for that reason.. we have 3 equations of motion .. to deal with accelerated motions..
ll be back in 10 ok?
but what do i do from here then? in short?
use equation of motion to set up an equation?
equation of motion?
what do you mean?
3 equations of motion?! haven't you dealt with accelerated motions before?
equations which connect, displacement, initial velocity, final velocity, time acceleration?
oh 'suvat' equations: v=u+at s=1/2(u+v)t v^2=u^2 + 2as
i'm not on the topic with those yet thought so they shouldn't be nessecary
any tips?
done it.
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