Please help, I have been looking at this for awhile now.

The height (in meters) of a projectile shot vertically upward from a point 3 m above ground level with an initial velocity of 24.5 m/s is
h = 3 + 24.5t − 4.9t2
after t seconds. (Round your answers to two decimal places.)

(a) Find the velocity after 2 s and after 4 s.
v(2) = m/s (i think 4.9)
v(4) = m/s (i think -14.7)

(b) When does the projectile reach its maximum height?
s

(c) What is the maximum height?
m

(d) When does it hit the ground?
s

(e) With what velocity does it hit the ground?
m/s

Question

Please help, I have been looking at this for awhile now.

The height (in meters) of a projectile shot vertically upward from a point 3 m above ground level with an initial velocity of 24.5 m/s is 
h = 3 + 24.5t − 4.9t2
 after t seconds. (Round your answers to two decimal places.)

(a) Find the velocity after 2 s and after 4 s.
v(2)	 = 	  m/s (i think 4.9)
v(4)	 = 	  m/s (i think -14.7)

(b) When does the projectile reach its maximum height?
  s

(c) What is the maximum height?
  m

(d) When does it hit the ground?
  s

(e) With what velocity does it hit the ground?
  m/s

anonymous · Answer

a-
ur answer is right

anonymous · Answer

thanks, I figured it out eventually @esamalaa