Find the equation of the line that has the given slope and passes through the given point. m=1/2, (2,-2)
there are two ways to do this....either use y = mx + b or use y - y1 = m(x - x1). I prefer y = mx + b myself, because to me it is easier. y = mx + b slope(m) = 1/2 (2,-2) x = 2 and y = -2 now we sub...we are looking for b, the y intercept -2 = 1/2(2) + b -2 = 1 + b -2 - 1 = b -3 = b so our equation is : y = 1/2x - 3
the other form, point-slope form (y - y1 = m(x - x1)....I only use that form if it specifically asks me to...but that is just me
So for like (-3,2) (-6,-7) My answer would be y=3x+11
now for that, you fist need to find the slope by using the slope formula : slope = (y2 - y1) / (x2 - x1). And once you find the slope, you use the y = mx + b thing.
I think that's what I did
oh...I am sorry...I didn't check the answer. If you did that, then your answer could be correct, unless it is asking to put it in standard form
It wants slope intercept :)
Yea its right
slope is correct...3 y = mx + b m = 3 (-3,2) x = -3 and y = 2 sub 2 = 3(-3) + b 2 = -9 + b 2 + 9 = b 11 = b yes...your equation is : y = 3x + 11
Yay thank you :) I will be posting more questions
I wish I could help but I am fixing to leave to go somewhere. I will be back on later.
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