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Find the equation of the line that passes through (5,3) and is perpendicular to y=5x-6
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@johnweldon1993 is it y=5x-22
Not quite...since I see perpendicular that means your slope should be the negative reciprocal of the other lines slope...so it's slope should be -1/5x
Dangit.
I may do another assignment since I am already going to be late to work haha. Will you be on for the next hour incase I need help?
So with that slope and that point, use the point slope form \[\large y - y_0 = m(x - x_0)\] putting in your numbers we have \[\large y - 3 = -\frac{1}{5}(x - 5)\] \[\large y = -\frac{1}{5}x + 4\] Would be your equation
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and no sorry I have to head to work in a few minutes!
Ah ok thank you.
Glad to help :) anytime :)
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