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Mathematics 7 Online
OpenStudy (anonymous):

plz som help :) will fan+medal

OpenStudy (anonymous):

Show that (1 + z)2 = 1 + 2z + z2.

OpenStudy (lastdaywork):

\[(1+z)^2 = (1+z)(1+z)\] By distributive law \[(1+z)(1+z) = 1(1+z) + z(1+z)\] Can you do the rest ??

OpenStudy (anonymous):

umm so easily using distributive lol i thought there is som kind of trick :|

OpenStudy (anonymous):

i thought i had to prove distributive or somthing :o

OpenStudy (anonymous):

well, ty @LastDayWork !

OpenStudy (lastdaywork):

You're welcome :)

OpenStudy (anonymous):

btw, nice mask :P

OpenStudy (lastdaywork):

^_^

OpenStudy (nincompoop):

you prove by giving all the laws and theorems for all the steps you make

OpenStudy (nincompoop):

distributive property is one of them

OpenStudy (anonymous):

so do u have somthing else ?

OpenStudy (anonymous):

i ment other method/thm to prove ?

OpenStudy (nincompoop):

laws of exponent

OpenStudy (anonymous):

hmm u mean binomial ?

OpenStudy (nincompoop):

you can

OpenStudy (anonymous):

sry but what is "laws of exponent " ?!

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