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plz som help :) will fan+medal
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Show that (1 + z)2 = 1 + 2z + z2.
\[(1+z)^2 = (1+z)(1+z)\] By distributive law \[(1+z)(1+z) = 1(1+z) + z(1+z)\] Can you do the rest ??
umm so easily using distributive lol i thought there is som kind of trick :|
i thought i had to prove distributive or somthing :o
well, ty @LastDayWork !
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You're welcome :)
btw, nice mask :P
^_^
you prove by giving all the laws and theorems for all the steps you make
distributive property is one of them
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so do u have somthing else ?
i ment other method/thm to prove ?
laws of exponent
hmm u mean binomial ?
you can
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sry but what is "laws of exponent " ?!
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