Question

Finish writing the equation of the line y=-1/3x-? given the points (3, -5) and (-6, -2). Type only the part that is missing in the equation.

Answer 1

As a general equation is
y = mx+c
where m is slope of the line and c is the y intercept
since both the point the points are in the line, so u can plug in either (3,-5) or(-6,-2) to determine the missing link in the equation

Answer 2

i get confused on where to plug them in

Answer 3

it is given
y = -(1/3)x -?
plug them here
now u can determine your missing link in the equation

Answer 4

(3, -5) and (-6, -2)
\[\huge y-y_1 =m(x-x_1) \]
\[\huge \rightarrow y-(-5) =\frac{-5-(-2)}{3-(-6)}(x-3)\]
\[\huge \rightarrow y+5) =\frac{-5+2}{3+6}(x-3)\]
\[\huge \rightarrow y+5 =\frac{-3}{9}(x-3)\]
\[\huge \rightarrow y+5 =-\frac{1}{3}(x-3)\]
\[\huge \rightarrow y+5 =-\frac{1}{3}x+1\]
\[\huge \rightarrow y =-\frac{1}{3}x+1-5\]
\[\huge \rightarrow y =-\frac{1}{3}x-4\]

Hence the missing part in the eq. is 4

@felicagail