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Factor x^2 - 3 x^2-3^2= (x+3)(x-3) Did I do this right?
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nope
What did I do wrong?
\[x^2-3=\left( x+\sqrt{3} \right)\left( x-\sqrt{3} \right)\]
Factor x^2 - 9
I know I was supposed to do the square root thing. But I didn't know how to do it on here.
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How do you factor x^2-9?
x^2-3^2= (x+3)(x-3)
for this you are correct.
Okay now I see were I made the mistake. Thank you @skullpatrol and @surjithayer.
Thanks for asking :)
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