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ax-b=c, for x
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ok it would be x=c/a+b
ax-b=c ax= b+c \[\huge x= \frac{b+c}{a}\]
c+b because you moved the b not the c
why not b+c ? @Dmb1215
because when you move the b over it goes behind the c because you move it to the end
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but 2+3 = 3+2 = 5, why?
put a negative number there
-3-3=-6 ok 3--3= 0
But there is no negative number!!!!!!!!
i know that its just vairables but what if one of the variables = a negative number
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I have my sense to utilize in that case, dear. don't fall in useless argument.
one sec i will find out whos right
i will take that back and im sorry for argueing with you i used mathway.com and it told me you were right.
@Its Ok, You are most welcome
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