Question

4/7 of a class earned A's 6 did not, how many earned A's? I asked incorrectly last time.

Answer 1

Lete there are X stidents in the class
4/7 of a class earned A and 6 did not
Therefore no. of students who earned= (X-6)
Hence: 4/7 of X = X-6
\[\huge \frac{4}{7} \times X = X-6 \rightarrow \huge \frac{4X}{7} = X-6\]
\[\rightarrow \huge 4X =7(X-6) \rightarrow 4X = 7X -42\]
\[\huge \rightarrow 42= 7X -4X \]
\[\huge \rightarrow 3X =42 \rightarrow X = \frac{42}{3} = 14\]

Hence 14 students earned A's in the class.

@chadadd3

Answer 2

Sorry,
Since X is the total number of students
So number of students earned A= X-6= 14-6 = 8

Hence 8 students earned A's.
@chadadd3