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Integration help!!!
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\(\Psi = \sqrt{\dfrac 2 L} sin{(\dfrac {2\pi x}{L})}\) for 0\(\le\)x\(\le\) L. Determine the expectation value. The expectation value <x> is calculated as \[<x> = \int_{-\infty}^{+\infty} \Psi^* x \Psi dx\] where \(\Psi^*\) is the complex conjugate of \(\Psi\). Anyone know how to do the calculation?
@roadjester seems u are doing one dimensional potential well problem
Indeed, except no one wants to help in physics and this IS integration which is calculus.
Unless you want to help me with the full problem? I'll post it in the physics group
yeah i will try to help u out
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http://openstudy.com/study#/updates/5312de5fe4b045fb28bb69fb Let me just add the rest of the problem.
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