Question

? Help ? 6x^2 + 7xy + 1 - y^2 =0 use the quadratic formula to solve for x in terms of y and y in terms of x

Answer 1

have you covered the quadratic formula yet?

Answer 2

here a=6,b=7y,c=1-y^2
use quadratic formula

Answer 3

similarly to solve for y in terms of x
a=-1,b=7x,c=6x^2+1
use quadratic formula.

Answer 4

we have barely covered it

Answer 5

\[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

Answer 6

ik the formula my problem is trying to figure out what to plug in when i have a weird equation

Answer 7

\[x=\frac{ -7y \pm \sqrt{\left( 7y \right)^2-4*6\left( 1-y^2 \right)} }{2*6 }\]

Answer 8

simplify it.
similarly for y

Answer 9

i got -7y^2/12 + or minus 5y^2/12

Answer 10

\[x=\frac{ -7y \pm \sqrt{49y^2-24+24y^2} }{12 }=\frac{-7y \pm \sqrt{73y^2-24} }{ 12 }\]

Answer 11

\[y=\frac{ -7x \pm ^{\sqrt{\left( 7x \right)^2-4*-1*\left( 6x^2+1 \right)}} }{ 2*-1 }\]
simplify it.