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Biology 21 Online
OpenStudy (anonymous):

Help on number 6 and 7 a and d please

OpenStudy (anonymous):

OpenStudy (anonymous):

also any solution injected directly into veins and arteries must be ____ with blood serum. Is i t hypertonic or isotonic?

OpenStudy (4n1m0s1ty):

So for number 6, we have a graph of an enzyme's activity marked at various pH's. The temperature is also changed for three different cases 10, 30, and 100 C. Now, enzyme activity is primarily determined by environmental pH and temperature, which is what this graph shows. Notice that the activity of the enzyme for the three curves peaks at about pH ~ 7.4 (which for most biological systems is fairly standard). The second thing to note is that the temperature also affects the activity level. 30 C seems to be the most optimal (your body's temperature is around this temp). At 10 C, enzyme activity decreases since there is less energy for the reactions. At 100 C, you are basically denaturing the enzyme meaning that you are breaking it apart (like cooking), and that's why you basically have zero activity. So for question 6a, the difference is due to temperature for the reason I explained above, and for 6b its because the enzyme becomes denatured.

OpenStudy (4n1m0s1ty):

Solutions injected into blood must be isotonic.

OpenStudy (anonymous):

ahh you're the best thank youuuuuu! <3

OpenStudy (anonymous):

for 6C, what it become higher or stay around the same?

OpenStudy (4n1m0s1ty):

Just a sec, I have a few emails to finish, should be about 5 mins.

OpenStudy (anonymous):

Alrighty !

OpenStudy (4n1m0s1ty):

Ok so for 6c, you should get the same curve as before. You may be thinking, if we lower the temperature to 30 C, why don't we get the same curve as A? That's because when you denature an enzyme, you basically remove all the hydrogen bonds that give it its tertiary structure. Once, you get rid of these, you can't have them "renature" them again unless they are placed back into the original environment.

OpenStudy (anonymous):

Makes a lot of sense thank you! lol better than my teacher

OpenStudy (anonymous):

So for 7, the ones I got wrong, could you help me with those?

OpenStudy (4n1m0s1ty):

For problem 7a, I can't exactly see the whole picture, but I think its a triglyceride. For problem 7d, I think its cellulose, since they are rotated 180 each time. Stach would be oriented the same direction.

OpenStudy (4n1m0s1ty):

Starch*

OpenStudy (anonymous):

Alrighty. Thank you so much ! :) Hopefully I do well on this test

OpenStudy (4n1m0s1ty):

Good luck! Is this high school or university bio?

OpenStudy (anonymous):

This is gr 12 university bio

OpenStudy (anonymous):

and thank you!

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