Question

What are the approximate solutions of 2x^2 -x + 10 = 0 ?

Answer 1

one approach
what are the factors of 20 such that when you add them you get -1?

Answer 2

so using -5 and +4
2x^2 -5x +4x + 10 =0
regroup and factor
2x(x +2) -5(x +2) =0
common factor (x + 2)
(2x-5)(x+2)=0

2x-5 = 0; x + 2 = 0
solve for x

Answer 3

(2x - 5) (x + 2) . When you factor that out you get 2x^2 - x -10. It should be a positive 10. I believe you have to use the quadratic formula.

Answer 4

you are right sorry but the method for factoring is correct

the other approach is to use the quadratic formula
first identify a, b and c
using x = -b +/-rt of (b^2-4*a*c) / 2a
plug the values of a, b and c then solve
a = 2, b = -1 and c = 10