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How do you simplify this? Question attached. I'm lost, any hints or reference to any websites would be greatly appreciated.
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sin(A+b)= sinA cos B +sin B +cos A
\[\sin( \theta+90)=\sin \theta \cos90 +\sin 90 \cos \]
oh ok, so do you basically expand the sine function and then do the multiplication and division?
yes cos90= 0 soo the first part equals zero we have only the second part
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ok. I just got this, im not sure if it can be simplified any further
r u allowed to use the calculator u can simplify 0.6/sin12
yes I think so
okay then do it it equals 2.8858
so would it be equal to 2.8858Wcos(angle) as the most simplified form?
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yup no other simplification to be done
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